const_cast conversion
From Cppreference
Converts between types when no implicit conversion exists.
Contents |
[edit] Syntax
| const_cast < new_type > ( expression ) | |||||||||
All expressions return an value of type new_type.
[edit] Explanation
All above conversion operators compute the value of expression, convert it to type and return the resulting value. Each conversion can take place only in specific circumstances or the program is ill formed.
Casts type to an equivalent type with different cv-qualifiers.
| This section is incomplete |
[edit] Keywords
[edit] Example 1
#include <iostream> int main() { int i = 3; const int& cref_i = i; const_cast<int&>(cref_i) = 4; std::cout << "i = " << i << '\n'; }
Output:
i = 4
[edit] Example 2
#include <iostream> struct type { type() :i(3) {} void m1(int v) const { // this->i = v; // compile error: assignment of member 'type::i' in read-only object const_cast<type*>(this)->i = v; } int i; }; int main() { type t; t.m1(4); std::cout << "type::i = " << t.i << '\n'; }
Output:
type::i = 4