std::is_compound
From Cppreference
Defined in header <type_traits>
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template< class T >
struct is_compound; |
(C++11 feature) | |
If T is a compound type (that is, array, function, object pointer, function pointer, member object pointer, member function pointer, reference, class, union, or enumeration, including any cv-qualified variants), provides the member constant value equal true. For any other type, value is false.
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Inherited from std::integral_constant
Member constants
value | true if T is a compound type , false otherwise (public static member constant) |
Member functions
operator bool | converts the object to bool, returns value (public member function) |
Member types
Type | Definition |
value_type | bool |
type | std::integral_constant<bool, value> |
[edit] Notes
Compound types are the types that are constructed from fundamental types. Any C++ type is either fundamental or compound.
[edit] Equivalent definition
template< class T > struct is_compound : std::integral_constant<bool, !std::is_fundamental<T>::value> {}; |
[edit] Example
Output:
T is compound T is not a compound
[edit] See also
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checks if a type is fundamental type (class template) |
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checks if a type is scalar type (class template) |
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checks if a type is object type (class template) |
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checks if a type is an array type (class template) |